8" x mile²

I cheated. Googled it. Has something to do with curvature of the earth. Got tired of reading, so it’s either used by flat earthers to prove earth is flat…. Or it is actually how we determine said curvature.
 
Inspector #20 said:
Earth radius formula, IIRC.
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Correct, 8" x mile² is the trigonometry formula for the curvature of the earth as told to us by science. So that poses a question. If I am at the beach looking out to the water and an oil rig 25 miles out to see, there should be over 400 feet of observable curvature. Let's do the math.

25 miles x 25 = 625
625 x 8" = 5,000"
5,000" ÷ 12 = 416.666'

According to science there should be over 416 feet of curvature between the shore where I took the video below and to oil rig in the distance 25 miles from where I shot this footage 2 weeks ago at Sunset Beach near Huntington Beach. If there is indeed over 400 feet of curvature, why can we see this boat?

 
WavMixer said:
Correct, 8" x mile² is the trigonometry formula for the curvature of the earth as told to us by science. So that poses a question. If I am at the beach looking out to the water and an oil rig 25 miles out to see, there should be over 400 feet of observable curvature. Let's do the math.

25 miles x 25 = 625
625 x 8" = 5,000"
5,000" ÷ 12 = 416.666'

According to science there should be over 416 feet of curvature between the shore where I took the video below and to oil rig in the distance 25 miles from where I shot this footage 2 weeks ago at Sunset Beach near Huntington Beach. If there is indeed over 400 feet of curvature, why can we see this boat?

Click to expand...
Water seeks it's own level?
 
Earth is actually not a perfect sphere. And yeah, the water thing too. Therefore, while the equation can tell us things in a general sense...not too sure we can rely on it to answer why we can see that boat. Other answers may lie in the way light is bent around objects with gravity, or the scientific reason why a mirage is a thing. But my guess would be that 25 miles over water (level, because water) may be insignificant enough to make much of a difference as far as observable curvature.

Interesting question.
 
The Earth ia an ellipsoid, the calcs for curvature are dependent on many details.

The "mean avg" of curvature is 0.67' (8") per mile. Like in all averages there are many extremes that are in that math.

I've done water transfers, of elevation across Lake Michigan that would shock a person on how flat it is. Of course depending on wind, gravity, etc..
 
steveb63 said:
The Earth ia an ellipsoid, the calcs for curvature are dependent on many details.

The "mean avg" of curvature is 0.67' (8") per mile. Like in all averages there are many extremes that are in that math.

I've done water transfers, of elevation across Lake Michigan that would shock a person on how flat it is. Of course depending on wind, gravity, etc..
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According to science, water curves around the surface of the earth, just look at any globe. Earth is covered with water over 70% of the globe. If Earth is an oblate spheroid, there should be an observable, measurable curve.

1665072718748.jpeg

If gravity is holding us to the globe, holding water to the globe, this would appear that the surface of the water curves to conform the the surface of the Earth. Science tells us that the Earth circumference is 24, 902 miles. This would put the curvature of 416 feet between my camera and the boat. If science is accurate with the measurement of the Earth, I should not have been able to capture this boat 25 miles away. Simple math tells me that scientists do not know the actual size of the earth or, scientists are misleading us.
 
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I'm thinking plane geometry is muddled in these measurements.
Using the 8" oer mile solution does not account for anomalies- mountains, plateaus etc..
The line segment being used is one mile, when the surface is much larger.

To explain a measurement on the earth's surface a level line is used to describe something curved.

Look into the plane geometry solutions for this same formula, this is why the surveyor or engineer tests are two days.

Lol, most interesting at least to me.

Grid to ground corrections.
 
WavMixer said:
Correct, 8" x mile² is the trigonometry formula for the curvature of the earth as told to us by science. So that poses a question. If I am at the beach looking out to the water and an oil rig 25 miles out to see, there should be over 400 feet of observable onsidercurvature. Let's do the math.

25 miles x 25 = 625
625 x 8" = 5,000"
5,000" ÷ 12 = 416.666'

According to science there should be over 416 feet of curvature between the shore where I took the video below and to oil rig in the distance 25 miles from where I shot this footage 2 weeks ago at Sunset Beach near Huntington Beach. If there is indeed over 400 feet of curvature, why can we see this boat?

Click to expand...
They may have failed to consider, earth in Orange County is an oblate spheroid.
 
So if water finds it's own level, and gravity holds the water down, there would be no anomalies other than waves in the ocean regarding my video.

Lake Michigan is 307 miles long and 118 miles across at its widest point. It has an average surface elevation of 577.5 feet (176.0 meters), although these water levels have ranged between about 576.0 feet and 582.3 feet over the past 100 years. No waves for anomalies to bring into the equation. We should be able to notice the curvature of the lake just as we should be able to detect curvature of the ocean, correct?
 
WavMixer said:
According to science, water curves around the surface of the earth, just look at any globe. Earth is covered with water over 70% of the globe. If Earth is an oblate spheroid, there should be an observable, measurable curve.

View attachment 86391

If gravity is holding us to the globe, holding water to the globe, this would appear that the surface of the water curves to conform the the surface of the Earth. Science tells us that the Earth circumference is 24, 902 miles. This would put the curvature of 416 feet between my camera and the boat. If science is accurate with the measurement of the Earth, I should not have been able to capture this boat 25 miles away. Simple math tells me that scientists do not know the actual size of the earth or, scientists are misleading us.
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The ocean is actually lime Jello; therefore sticks to the surface.
 
A simplified version has us measuring the surface of a basketball with 3'', 6'' and 2.0' rulers.

It will be different with each segment depending on length.

Now throw in the geometry of the earth, not a "true" circle. Couple it with atmospheric anomaly, earth being a "squashed" circle with our varied surface features all add up to this "rule of thumb"

I'm going shopping with Mrs. Steve here in a few, but look forward to further discussion.

Lol I just love this poop Ha!
 
WavMixer said:
According to science, water curves around the surface of the earth, just look at any globe. Earth is covered with water over 70% of the globe. If Earth is an oblate spheroid, there should be an observable, measurable curve.

View attachment 86391

If gravity is holding us to the globe, holding water to the globe, this would appear that the surface of the water curves to conform the the surface of the Earth. Science tells us that the Earth circumference is 24, 902 miles. This would put the curvature of 416 feet between my camera and the boat. If science is accurate with the measurement of the Earth, I should not have been able to capture this boat 25 miles away. Simple math tells me that scientists do not know the actual size of the earth or, scientists are misleading us.
Click to expand...
Or, that there's more to the science involved than just that math.

Earth is actually a torus...like a donut. But why have they been hiding this from us??


1541789697177-DonutEarth.jpeg




It is both flat, AND round.
 
WavMixer said:
So if water finds it's own level, and gravity holds the water down, there would be no anomalies other than waves in the ocean regarding my video.

Lake Michigan is 307 miles long and 118 miles across at its widest point. It has an average surface elevation of 577.5 feet (176.0 meters), although these water levels have ranged between about 576.0 feet and 582.3 feet over the past 100 years. No waves for anomalies to bring into the equation. We should be able to notice the curvature of the lake just as we should be able to detect curvature of the ocean, correct?
Click to expand...
I’m at lunch and pressed for time…but…the moon pulls at the oceans (and large bodies of water etc)…that is what creates the tidal bulge that varies curvature over oceans.

Atmospheric refraction can have effect on what is visible over the horizon.
 
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